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X=9X^2-24X
We move all terms to the left:
X-(9X^2-24X)=0
We get rid of parentheses
-9X^2+X+24X=0
We add all the numbers together, and all the variables
-9X^2+25X=0
a = -9; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-9)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-9}=\frac{-50}{-18} =2+7/9 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-9}=\frac{0}{-18} =0 $
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